Digits Calculation and Explanation

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There are three numbers 1382882, 1073751, and 1000143804. Please solve this riddle about them: "Add all the individual digits in the two different seven-digit numbers plus those in the ten-digit number, and divide the sum by the largest pair of digits in 1073751, treating the pairs a single number. Now subtract the sum of the lesser of the most frequently appearing digits in all three numbers from the quotient and multiply the difference by the greater of the most frequently appearing digist in all three numbers. What is the product?" After solving, also please explain your work step by step for how you obtained your answer.All right, let's break down the riddle step by step:

Step 1: Add all the individual digits in the numbers

1. 1 + 3 + 8 + 2 + 8 + 8 + 2 = 32
2. 1 + 0 + 7 + 3 + 7 + 5 + 1 = 24
3. 1 + 0 + 0 + 0 + 1 + 4 + 3 + 8 + 0 + 4 = 21

Total sum = 32 + 24 + 21 = 77

Step 2: Find the largest pair of digits in 1073751

The pairs are 10, 07, 73, 37, 75, 51. The largest is 75.

Divide the sum by this number: 77 ÷ 75 = 1.0267 (rounded off to four decimal places)

Step 3: Find the most frequently appearing digits in all three numbers

First, we'll list out the frequency of each digit in all three numbers:

0: 5 times 1: 5 times 2: 2 times 3: 3 times 4: 2 times 5: 2 times 7: 3 times 8: 4 times

The most frequently appearing digits are 0 and 1, both appearing 5 times.

Step 4: Subtract the lesser from the quotient and multiply by the greater

Lesser = 0 and Greater = 1.

Subtracting: 1.0267 - 0 = 1.0267

Multiplying: 1.0267 × 1 = 1.0267

The answer to the riddle is ( \approx ) 1.0267.

Note: The numbers have been rounded for clarity, but this is approximately the answer the riddle is asking for.

Digits Calculation and Explanation created at Tue Jan 20 1970 14:06:45 GMT+0000 (Coordinated Universal Time)