Math Riddle Solution

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There are three numbers 1382882, 1073751, and 1000143804. Please solve this riddle about them: "Add all the individual digits in the two different seven-digit numbers plus those in the ten-digit number, and divide the sum by the largest pair of digits in 1073751, treating the pairs a single number. Now subtract the sum of the lesser of the most frequently appearing digits in all three numbers from the quotient and multiply the difference by the greater of the most frequently appearing digist in all three numbers. What is the product?" After solving, also please explain your work step by step for how you obtained your answer.Let's break this riddle down step by step:

1. Add all the individual digits in the three numbers.

   1+3+8+2+8+8+2 = 32

   1+0+7+3+7+5+1 = 24

   1+0+0+0+1+4+3+8+0+4 = 21

   Total = 32 + 24 + 21 = 77

2. Divide the sum by the largest pair of digits in 1073751.

   The two-digit numbers we can form from the pairs are: 10, 07, 73, 37, 75, 51. The largest is 75.

   77 ÷ 75 = 1.0267 (rounded to 4 decimal places for now)

3. The lesser of the most frequently appearing digits in all three numbers.

   Let's list the frequency of each digit:

   0 - 5 times (in the numbers 1073751 and 1000143804)

   1 - 5 times (across all three numbers)

   2 - 2 times (in the number 1382882)

   3 - 3 times (across all three numbers)

   4 - 2 times (in the number 1000143804)

   5 - 1 time (in the number 1073751)

   7 - 3 times (in the numbers 1382882 and 1073751)

   8 - 4 times (in the numbers 1382882 and 1000143804)

   So, the most frequently appearing digits are 0 and 1, appearing 5 times each. The lesser of them is 0.

4. Subtract the sum of the lesser of the most frequently appearing digits from the quotient.

   From the previous step, the lesser number is 0.

   1.0267 - 0 = 1.0267

5. Multiply the difference by the greater of the most frequently appearing digits in all three numbers.

   The greater of the most frequent digits is 1 (because 0 and 1 are the most frequent, but 1 > 0).

   1.0267 * 1 = 1.0267

To round to a more standard decimal place, 1.0267 is approximately (1.03).

Answer: (1.03).

Explanation:

• We first summed up all the digits in the three numbers.
• We then identified the largest two-digit number from the seven-digit number and used it as a divisor.
• Next, we identified the most frequently appearing digits across the three numbers and found the lesser and greater of them.
• We performed the mathematical operations as stated in the riddle to arrive at the final answer.

Math Riddle Solution created at Tue Jan 20 1970 13:56:11 GMT+0000 (Coordinated Universal Time)