JS Regex for Ref Replacement

TODO: collapasable, copyable, download, etc

I want to write a JS regex that can match any number of this \ref[123-432-234] and replace it with this [Source123-432-234](#123-432-234). Can you give me the regex an example usage?Sure! To create a JavaScript regular expression that matches the pattern \ref[123-432-234] and replaces it with [Source123-432-234](#123-432-234), you can use the following regex pattern and replacement logic.

Regular Expression

• Pattern: \\ref\[(\d+-\d+-\d+)\]
• Explanation:
  • \\ref: Matches the literal string \ref. Double backslash \\ is used because in JavaScript, backslash \ is an escape character.
  • \[(\d+-\d+-\d+)\]: Matches a sequence of digits and hyphens enclosed in square brackets. The parentheses () capture the sequence for later use in the replacement.

Replacement String

• Replacement: [Source$1](#$1)
• Explanation:
  • $1 refers to the first captured group in the pattern (the sequence of digits and hyphens).

JavaScript Example

const regex = /\\ref\[(\d+-\d+-\d+)\]/g;
const str = "This is a reference \\ref[123-432-234] and another \\ref[111-222-333]";
const replacedStr = str.replace(regex, '[Source$1](#$1)');

console.log(replacedStr);

This JavaScript code will search for all occurrences of the pattern \ref[123-432-234] (and similar patterns with different numbers) in the string str and replace them with the specified format [Source123-432-234](#123-432-234). The g flag in the regex pattern is used to perform a global search and replace all matches in the string.I am having a JSON.parse exception, because of some special characters. Can you generate a console.log function that would iterate through a string and get the character code and then ignore a-z, A-Z, 0-9, space, tab, etc and then print a list of interesting character codes in octal?Certainly! To create a JavaScript function that iterates through a string, identifies characters that are not within the ranges of a-z, A-Z, 0-9, space, and tab, and then prints their character codes in octal format, you can follow this approach:

1. Iterate over each character in the string.
2. Check if the character is not a letter (a-z, A-Z), a digit (0-9), a space, or a tab.
3. If the character is "interesting" (not one of the above), convert its character code to octal and print it.

Here's a sample JavaScript function that does this:

function printInterestingCharCodes(str) {
    const interestingChars = [];

    for (let i = 0; i < str.length; i++) {
        const char = str[i];
        const charCode = char.charCodeAt(0);

        // Check if character is not a letter, digit, space, or tab
        if (!/[a-zA-Z0-9 \t]/.test(char)) {
            // Convert character code to octal
            const octalCode = charCode.toString(8);
            interestingChars.push(`${char} (\\${octalCode})`);
        }
    }

    if (interestingChars.length > 0) {
        console.log("Interesting character codes in octal:", interestingChars.join(', '));
    } else {
        console.log("No interesting characters found.");
    }
}

// Example usage
const yourString = "Your string here, with special characters like é, ü, etc.";
printInterestingCharCodes(yourString);

This function will log a list of "interesting" characters found in the string yourString, along with their octal character codes. If no such characters are found, it will log a message indicating that. Replace "Your string here, with special characters like é, ü, etc." with the actual string you want to check.

JS Regex for Ref Replacement created at Tue Jan 20 1970 16:17:23 GMT+0000 (Coordinated Universal Time)